Odpowiedź:
sin α = [tex]\frac{4}{5}[/tex] α ∈ ( 0° , 90° )
cos²α = 1 - sin²α = [tex]\frac{25}{25} - \frac{16}{25} = \frac{9}{25}[/tex]
więc
cos α = [tex]\sqrt{\frac{9}{25} } = \frac{3}{5}[/tex]
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Szczegółowe wyjaśnienie:
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Odpowiedź:
sin α = [tex]\frac{4}{5}[/tex] α ∈ ( 0° , 90° )
cos²α = 1 - sin²α = [tex]\frac{25}{25} - \frac{16}{25} = \frac{9}{25}[/tex]
więc
cos α = [tex]\sqrt{\frac{9}{25} } = \frac{3}{5}[/tex]
===================
Szczegółowe wyjaśnienie: