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Jawablimit (x →-2) (ax² + bx + 6)/ (x² -x - 6) = 1/5
bentuk 0/0 untuk x = -2
a(4) + b(-2) + 6= 0
4a - 2b + 6 = 0
2a - b = -3 ...(i)
d/hospital
(2ax + b)/(2x -1) = 1/5 untuk x= -2
(-4a + b)/ (-5) = 1/5
-4a + b = -1 ..(ii)
(I dan ii)
2a - b = -3
-4a + b = - 1 (+)
-2a = - 4
a = 2
b = 2a + 3
b = 4 + 3
b = 7
ab = 14