Question

5 log3=a , 3log2 =b
6log 75=

Answer 1

^6log75 = ^5log 75 / ^5log 6
= ^5log( 3 x 5^2) / ^5 log (2x3)
= (^5log 3 + 2 ^5log5) / (^5log3 + ^5log2)
= (a+2) / (a + ab)