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Panjang Busur = 3/5 keliling lingkaran
= 3/5 . 2. phi. r
= 6/5 . 22/7 . 30
= 792/7 cm
Keliling alas kerucut = 2 phi r
r= keliling ÷ 2. phi
r=792/7 ÷ 2. 22/7
r= 792/7 ÷ 44/7
r= 792/7 x 7/44
r= 792/44
r= 18 cm
jadi r kerucut = 18 cm dan s kerucut = r lingkaran= 30
maka
t²=s²-r²=30²-18²=900-324=576
t=√576= 24
Jadi tinggi kerucut adalah 24 cm