Question

Pd segitiga abc, sin BAC = 3/5 jika panjang sisi AC = 10 CM dan AB = 4 CM, panjang sisi BC adalah?

Answer 1

Sin A = 3/5
cos A = 4/5
BC^2 = AB^2 + AC^2 - 2.AB.BC.cos A
= 4^2 + 10^2 - 2.4.10.4/5
= 16 + 100 - 64
= 52cm
BC = √52 = 2√13 cm