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Tenemos.
2a√5 =
√((2a)² . 5) =
√(2² a² * 5) =
√(4a² . 5) =
√20a²
5x.⁴√2 =
⁴√((5x)⁴. 2 =
⁴√(5⁴ . x⁴ . 2)
⁴√625 . 2x⁴ =
⁴√1250x⁴
2∛2 =
∛((2)³ . 2) =
∛(8 . 2) =
∛16
2.⁷√2n =
⁷√((2n .(2) =
⁷√(2n . 128)
⁷√256n