5. Hallar: A = cos53' . sec53° + sen37" . sec53 b) 2 e) 4 a) 1 d) S c) 3.... Question from @pgargatehernandez35

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5. Hallar: A = cos53' . sec53° + sen37" . sec53 b) 2 e) 4 a) 1 d) S c) 3

Explicación paso a paso:

Cos 53=3/5

SEC 53=5/3

Sen 37=3)5

entonces reemplazamos

A=(3/5)(5/3) +(3/5)(5/3) simplificando

A=1+1

A=2

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