Respuesta: 3
Explicación paso a paso:
Lim (x⇒0) {[ (x²+3x-1)/x] + (1/x)} = Lim(x⇒0)[ (x²+3x)/x ]
= Lim(x⇒0) [ x(x+3)/x ]
= Lim(x⇒0) [ x + 3 ]
= 0+3
= 3
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Respuesta: 3
Explicación paso a paso:
Lim (x⇒0) {[ (x²+3x-1)/x] + (1/x)} = Lim(x⇒0)[ (x²+3x)/x ]
= Lim(x⇒0) [ x(x+3)/x ]
= Lim(x⇒0) [ x + 3 ]
= 0+3
= 3