Question

Diketahui sin x =3/5 di kuadran II. DGN MNGUNAKN IDENTITAS TRIGONOMETRI. Tentukan
a. cosec x + cotan x
b sec'2 x
c. 3+3 tan'2 x

Answer 1

Sinx = de/mi = 3/5 karena sinx berada di kuad II maka sisi samping = -4

a. cscx + cotx = 1/sin + 1/tan = mi/de + sa/de = 5/3 + (-4)/3 = 1/3

b. sec²x = (1/cos)² = (mi/sa)² = (5/-4)² = 25/16

c. 3 + 3tan²x = 3 + 3(de/sa)² = 3 + 3(3/-4)² = 3 + 3(9/16) = 3 + 27/16 = 3 27/16 = 4 11/16

Maaf Jika salah^^