Question

jumlah dan hasil kali akar sebuah persamaan kuadrat berturut-turut adalah 8 2/5 dan 16. persamaan kuadrat tersebut adalah​

Answer 1

Persamaan Kuadrat

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[tex]ax {}^{2} + bx + c = 0 \\ x {}^{2} + (x_{1} + x_{2}) x+ (x_{1} \times x_{2}) = 0[/tex]

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Penyelesaian Soal

[tex]Pers.Kuadrat = x {}^{2} + (x_{1} + x_{2}) x+ (x_{1} \times x_{2}) = 0[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~=x {}^{2} + 8 \frac{2}{5} x + 16 = 0[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~=(x {}^{2} + 8 \frac{2}{5} x + 16 = 0)5[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~=5x {}^{2} + 5(8 \frac{2}{5} x) + 5(16)= 5(0)[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~=5x {}^{2} + 42x + 80 = 0[/tex]

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[tex]\begin{array}{lr}\texttt{Rate 1.0 Jika Kalian Iri dengan}\\\\ \texttt{Yang Mulia Maharaja Danial Alf'at}\end{array}[/tex] ☝️

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{15/03/23}}[/tex]