[tex](4\frac{2}{5}-2,5\cdot\frac{1}{2})+3:\frac{1}{6}+2,7-\frac{1}{5}=(4\frac{2}{5}-\frac{25}{10}\cdot\frac{1}{2})+3\cdot6+2\frac{7}{10}-\frac{1}{5}=\\\\=(4\frac{2}{5}-\frac{5}{2}\cdot\frac{1}{2})+18+2\frac{7}{10}-\frac{2}{10}=(4\frac{2}{5}-\frac{5}{4})+18+2\frac{5}{10}=(4\frac{2}{5}-1\frac{1}{4})+18+2\frac{1}{2}=\\\\=(4\frac{8}{20}-1\frac{5}{20})+18+2\frac{1}{2}=3\frac{3}{20}+18+2\frac{1}{2}=3\frac{3}{20}+18+2\frac{10}{20}=23\frac{13}{20}[/tex]
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[tex](4\frac{2}{5}-2,5\cdot\frac{1}{2})+3:\frac{1}{6}+2,7-\frac{1}{5}=(4\frac{2}{5}-\frac{25}{10}\cdot\frac{1}{2})+3\cdot6+2\frac{7}{10}-\frac{1}{5}=\\\\=(4\frac{2}{5}-\frac{5}{2}\cdot\frac{1}{2})+18+2\frac{7}{10}-\frac{2}{10}=(4\frac{2}{5}-\frac{5}{4})+18+2\frac{5}{10}=(4\frac{2}{5}-1\frac{1}{4})+18+2\frac{1}{2}=\\\\=(4\frac{8}{20}-1\frac{5}{20})+18+2\frac{1}{2}=3\frac{3}{20}+18+2\frac{1}{2}=3\frac{3}{20}+18+2\frac{10}{20}=23\frac{13}{20}[/tex]