[tex]\dfrac{2p-5}{3}=\dfrac{4}{5}[/tex]
[tex]5\cdot(2p-5)=3\cdot4\\\\10p-25=12[/tex]
[tex]10p=12+25\\\\10p=37[/tex]
[tex]10p:10=37:10\\\\\huge\boxed{p=3,7}[/tex]
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Rozwiązywanie równań pierwszego stopnia
[tex]\dfrac{2p-5}{3}=\dfrac{4}{5}[/tex]
[tex]5\cdot(2p-5)=3\cdot4\\\\10p-25=12[/tex]
[tex]10p=12+25\\\\10p=37[/tex]
[tex]10p:10=37:10\\\\\huge\boxed{p=3,7}[/tex]