Diketahui segitiga ABC siku siku di B dan panjang AB = 6 cm. titik D dan F pada AC sedemikian sehingga AF = CD = 4 cm. segitiga FED siku siku di D. nilai cos segita BAC = 3/7 dan sin segitiga DEF = 3/5
1. Panjang DF =...
2. Panjang EF =...
1. Panjang DF =...
2. Panjang EF =...
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Sudut BAC = DEC = DFEsudut BCA = DEF
cos BAC = AB/AC = 3/7
6/AC = 3/7
AC = 6 × 7/3 = 14 cm
DF = AC - 2AF = 14 - 2.4 = 6 cm
EF = FD sin DEF
EF = 6 . 3/5
EF = 3,6 cm