Respuesta:
[tex] = (4y \times 4y) + (12 - 15) \times 4y + (12 \times - 15) = 16 {y}^{2} - 3 \times 4y - 180 = 16 {y}^{2} - 12y - 180[/tex]
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Respuesta:
[tex] = (4y \times 4y) + (12 - 15) \times 4y + (12 \times - 15) = 16 {y}^{2} - 3 \times 4y - 180 = 16 {y}^{2} - 12y - 180[/tex]