Question

4(y-3)' = (2y-3) (2y-10)

Tanda ' itu berarti pangkat 2

Answer 1

4(y-3)' = (2y-3) (2y-10)
4 (y-3) (y-3) = 4y' - 20y - 6y + 30
4 (y' - 3y - 3y + 9) = 4y' - 26y + 30
4 (y' - 6y + 9) = 4y' - 26y + 30
4y' - 24y + 36 = 4y' - 26y + 30
4y' - 4y' - 24y + 26y + 36 - 30 = 0
2y + 6 = 0

Answer 2

4 (y-3)² = (2y-3) (2y-10) // 4 (y-3) (y-3) = 4y²-20y-6y+30 // 4 (y²-3y-3y+9) = 4y²-20y-6y+30 // 4 (y²-6y+9) = 4y²-26y+30 // 4y²-24y+36 = 4y²-26y+30 // 4y²-24y+36-4y²+26y-30=0 // 2y +6 =0 // klo gk salah