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1/3 (x+2) + 1/ 4 ( x+ 3) > 2
x+2/ 3 + x + 3/ 4 >2
aplicamos aspa
4x + 8 + 3x + 9 > 2
---------------------
12
7x +. 17 > 12(2)
7x >24 - 17
7x > 7
x > 7/7
x > 0
Respuesta x es mayor a 0 y el conjunto solución = {1,2,3,....,infinito}
espero te sirva....:)