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4cx² + 4dxy + 3cxy + 3dy² = ex² + 23xy + 6y²
4cx² + (4d + 3c)xy + 3dy² = ex² + 23xy + 6y²
jadi , 3d = 6 ----> d = 2
4d + 3c = 23
4(2) + 3c = 23
8 + 3c = 23
3c = 23 - 8
3c = 15
c = 5
e = 4c
= 4. 5
= 20
4cx² + 4dxy + 3cxy + 3dy² = ex² + 23xy + 6y²
4cx² + ( 4d + 3c ) xy + 3dy² = ex² + 23xy + 6y²
Ambil koefisien y² :
3dy² = 6y²
3d = 6
d = 2
Ambil koefisien xy :
( 4d + 3c ) xy = 23xy
4d + 3c = 23
4(2) + 3c = 23
8 + 3c = 23
3c = 15
c = 5
Ambil koefisien x² :
4cx² = ex²
4c = e
e = 4 × 5
e = 20