Como resuelvo las siguientes ecuaciones????
2m/7=44
1/4m+3=8
2m/7=44
1/4m+3=8
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2m/7=44 --> m = 44.7 /2 = 14
la segunda
1/4m+3=8 --> 1/4m = 8 -3 --> 1/4 m = 5 -->
primero pasamos el tres que es mas importante abarca todo
luego el 4 pasa multiplicando
1/4 m = 5 --> m = 5x4 -> m = 20