Materi : Fungsi dan Relasi
( x² - 2x + 3 )( x² - 2x + 3 )
= x² + x + 5 - 3( x² - 2x + 3 )² + 12
= x² + x + 17 - 3( x⁴ - 4x³ + 10x² - 12x + 9 )
= x² + x + 17 - 3x⁴ + 12x³ - 30x² + 36x - 27
= - 3x⁴ + 12x³ - 29x² + 37x - 10
Jumlah Koefisien tiap suku
(-3) + 12 + (-29) + 37 + (-10)
= 9 - 29 + 27
= 9 - 2
= 7
f(x) = 2x² - 5x + 1
g(x) = x - 4
h(x) = - 3x² + 2
____________/
P(x) = 2 . f(x) - ( g(x) . h(x) )
P(x) = 2( 2x² - 5x + 1 ) - ( [ x - 4 ][ - 3x² + 2 ] )
P(x) = 4x² - 10x + 2 - ( - 3x³ + 12x² + 2x - 8 )
P(x) = 4x² - 10x + 2 + 3x³ - 12x² - 2x + 8
P(x) = 3x³ - 8x² - 12x + 10
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Materi : Fungsi dan Relasi
Soal Nomor 4
( x² - 2x + 3 )( x² - 2x + 3 )
= x² + x + 5 - 3( x² - 2x + 3 )² + 12
= x² + x + 17 - 3( x⁴ - 4x³ + 10x² - 12x + 9 )
= x² + x + 17 - 3x⁴ + 12x³ - 30x² + 36x - 27
= - 3x⁴ + 12x³ - 29x² + 37x - 10
Jumlah Koefisien tiap suku
(-3) + 12 + (-29) + 37 + (-10)
= 9 - 29 + 27
= 9 - 2
= 7
Soal Nomor 5
f(x) = 2x² - 5x + 1
g(x) = x - 4
h(x) = - 3x² + 2
____________/
P(x) = 2 . f(x) - ( g(x) . h(x) )
P(x) = 2( 2x² - 5x + 1 ) - ( [ x - 4 ][ - 3x² + 2 ] )
P(x) = 4x² - 10x + 2 - ( - 3x³ + 12x² + 2x - 8 )
P(x) = 4x² - 10x + 2 + 3x³ - 12x² - 2x + 8
P(x) = 3x³ - 8x² - 12x + 10
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]