Respuesta:
Por el teorema de Pitágoras:
[tex](3\sqrt{10})^{2} =(3w)^{2} +(w)^{2} \\\\ 9(10)=9w^{2} +w^{2} \\ \\ 90=10w^{2} \\ \\ \frac{90}{10} =w^{2} \\ \\ 9=w^{2} \\ \\ \sqrt{9} =w\\ \\ 3=w\\ \\ Rpta: w=3[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
Por el teorema de Pitágoras:
[tex](3\sqrt{10})^{2} =(3w)^{2} +(w)^{2} \\\\ 9(10)=9w^{2} +w^{2} \\ \\ 90=10w^{2} \\ \\ \frac{90}{10} =w^{2} \\ \\ 9=w^{2} \\ \\ \sqrt{9} =w\\ \\ 3=w\\ \\ Rpta: w=3[/tex]