6/4 + 2√3
= 6/2(2 + √3)
= 6/2/(2 + √3)
= 3/2 + √3
= 3/2 + √3 × 2 - √3/2 - √3
= 3(2 - √3)/(2 + √3(2 - √3)
= 3(2 - √3)/(2(2) - (√3(√3)
= 3(2 - √3)/4 - 3
= 3(2 - √3)
= 3(2) - 3(√3)
= 6 - 3√3 (B)
Jawaban:
B.
Penjelasan dengan langkah-langkah:
[tex] \frac{6}{4 + 2 \sqrt{3} } \\ = \frac{\cancel2 \times 3}{\cancel2 \times (2 + \sqrt{3} )} \\ = \frac{3}{2 + \sqrt{3} } \\ = \frac{3}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ = \frac{6 - 3 \sqrt{3} }{4 - 3} \\ = 6 - 3 \sqrt{3} [/tex]
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Verified answer
6/4 + 2√3
= 6/2(2 + √3)
= 6/2/(2 + √3)
= 3/2 + √3
= 3/2 + √3 × 2 - √3/2 - √3
= 3(2 - √3)/(2 + √3(2 - √3)
= 3(2 - √3)/(2(2) - (√3(√3)
= 3(2 - √3)/4 - 3
= 3(2 - √3)
= 3(2) - 3(√3)
= 6 - 3√3 (B)
Jawaban:
B.
Penjelasan dengan langkah-langkah:
[tex] \frac{6}{4 + 2 \sqrt{3} } \\ = \frac{\cancel2 \times 3}{\cancel2 \times (2 + \sqrt{3} )} \\ = \frac{3}{2 + \sqrt{3} } \\ = \frac{3}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ = \frac{6 - 3 \sqrt{3} }{4 - 3} \\ = 6 - 3 \sqrt{3} [/tex]