[tex]\sqrt[4]3=3^{\frac{1}{4}}\\\\\sqrt[5]{27}=\sqrt[5]{3^3}=3^{\frac{3}{5}}\\\\\frac{1}{\sqrt[7]{3^4}}=(\sqrt[7]{3^4})^{-1}=(3^{\frac{4}{7}})^{-1}}=3^{-\frac{4}{7}}\\\\3*\sqrt[6]3=3*3^{\frac{1}{6}}=3^{1+\frac{1}{6}}=3^{1\frac{1}{6}}[/tex]
[tex]\sqrt{99}=\sqrt{9*11}=3\sqrt{11}\\\\\sqrt{500}=\sqrt{100*5}=10\sqrt5\\\\\sqrt{490}=\sqrt{49*10}=7\sqrt{10}[/tex]
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[tex]\sqrt[4]3=3^{\frac{1}{4}}\\\\\sqrt[5]{27}=\sqrt[5]{3^3}=3^{\frac{3}{5}}\\\\\frac{1}{\sqrt[7]{3^4}}=(\sqrt[7]{3^4})^{-1}=(3^{\frac{4}{7}})^{-1}}=3^{-\frac{4}{7}}\\\\3*\sqrt[6]3=3*3^{\frac{1}{6}}=3^{1+\frac{1}{6}}=3^{1\frac{1}{6}}[/tex]
[tex]\sqrt{99}=\sqrt{9*11}=3\sqrt{11}\\\\\sqrt{500}=\sqrt{100*5}=10\sqrt5\\\\\sqrt{490}=\sqrt{49*10}=7\sqrt{10}[/tex]