Respuesta:
[tex]3 x + \frac{1}{2} - \frac{1}{4} = x + 5 \\ 4(3x + \frac{1}{2} - \frac{1}{4} ) = 4(x + 5) \\ 12x + 2 - 1 = 4x + 20 \\ 12x + 1 = 4x + 20 \\ 12x - 4x = 20 - 1 \\ 8x = 19 \\ x = \frac{19}{8} [/tex]
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Respuesta:
[tex]3 x + \frac{1}{2} - \frac{1}{4} = x + 5 \\ 4(3x + \frac{1}{2} - \frac{1}{4} ) = 4(x + 5) \\ 12x + 2 - 1 = 4x + 20 \\ 12x + 1 = 4x + 20 \\ 12x - 4x = 20 - 1 \\ 8x = 19 \\ x = \frac{19}{8} [/tex]