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Diket :Jarak awal, r1 = 5 cm
Intensitas awal, I1 = I = 500 watt/m²
Intensitas akhir, I2 = 1/4.I
Tanya :
Jarak akhir, r2 = __?
Jawab :
Intensitas
I = P/A
I = P/(4.π.r²)
Krn I ~ 1/r²
Maka :
I2/I1 = (r1/r2)²
1/4.I / I = (5/r2)²
1/4 = (5/r2)²
√(1/4) = (5/r2)
1/2 = (5/r2)
r2 = 10 cm
Jadi pergeseran pendengar supaya intensitas nya menjadi 1/4 semula adalah :
Δr = r2 - r1
Δr = 10 - 5
Δr = 5 cm
Bergeser menjauhi sumber sejauh 5 cm dari posisi semula
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FZA