Question

4. Perhatikan gambar disamping! Nilai p adalah ....
a.10 cm
b.11 cm
c.12 cm
d.15 cm

dikasih caranya ya!!!​

Answer 1

Jawaban:

Sisi miring segitiga 1

BC² = AB² + AC²

BC² = 3² + 4²

BC² = 9 + 16

BC² = 25

BC = √25

BC = 5 cm

P = BD

BD² = CD² - BC²

BD² = 13² - 5²

BD² = 169 - 25

BD² = 144

BD = √144

BD = 12 cm

Jawaban: C. 12 cm

Answer 2

Verified answer

Jawaban:

Penyelesaian :

• a = 4 cm
• b = 3 cm
• c = 13 cm

Mencari nilai p

[tex] \sf {p}^{2} = {c}^{2} - {( \sqrt{ {a}^{2} + {b}^{2} } )}^{2}[/tex]

[tex] \sf {p}^{2} = {13}^{2} - {( \sqrt{ {4}^{2} + {3}^{2} } )}^{2}[/tex]

[tex] \sf {p}^{2} = {13}^{2} - {( \sqrt{16 + 9} )}^{2}[/tex]

[tex] \sf {p}^{2} = {13}^{2} - {( \sqrt{25} )}^{2}[/tex]

[tex] \sf {p}^{2} = {13}^{2} - ( {5}^{2} )[/tex]

[tex] \sf {p}^{2} = 169 - 25[/tex]

[tex] \sf {p}^{2} = 144[/tex]

[tex] \sf p = \sqrt{144} [/tex]

[tex] \sf p = \red{12 \: cm}[/tex]

'비상' (Svt)