Penjelasan:
Q4 + P3 = 180°
2x + 15 + 5x – 10 = 180°
7x + 5 = 180°
7x = 180 – 5
x = 175/7
a) x = 25°
b) P3 = 5x – 10
P3 = 5(25) – 10
P3 = 115°
c) Q2 = 2x + 15 → sudut bertolak belakang
Q2 = 2(25) + 15
Q2 = 65°
d) P1 + Q4 = 180° → sudut luar sepihak
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Penjelasan:
Q4 + P3 = 180°
2x + 15 + 5x – 10 = 180°
7x + 5 = 180°
7x = 180 – 5
x = 175/7
a) x = 25°
b) P3 = 5x – 10
P3 = 5(25) – 10
P3 = 115°
c) Q2 = 2x + 15 → sudut bertolak belakang
Q2 = 2(25) + 15
Q2 = 65°
d) P1 + Q4 = 180° → sudut luar sepihak