9 4/5 - 3 1/2
49/5 - 7/2
MCM de los denominadores
5 - 2 | 2
5 - 1 | 5
1 - 1
2 * 5 = 10
49/5 = 98/10
7/2 = 35/10
98 - 35 / 10
63/10
5 1/4 = 21/4
63/10 - 21/4
10 - 4 | 2
2 * 2 * 5 = 20
63/10 = 126/20
21/4 = 105/20
126 - 105/20
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Solución:
De un tubo metálico que media 9 4/5 metros, Iván utilizó 3 1/2
9 4/5 - 3 1/2
49/5 - 7/2
MCM de los denominadores
5 - 2 | 2
5 - 1 | 5
1 - 1
2 * 5 = 10
49/5 = 98/10
7/2 = 35/10
98 - 35 / 10
63/10
y luego 5 1/4 metros.
5 1/4 = 21/4
63/10 - 21/4
MCM de los denominadores
10 - 4 | 2
5 - 2 | 2
5 - 1 | 5
1 - 1
2 * 2 * 5 = 20
63/10 = 126/20
21/4 = 105/20
126 - 105/20
21/20