Question

4 Log 6 = m+1 , maka 9 log 8 =

Answer 1

2^2'log 2 + 2^2'log 3 = m + 1
1/2 + 1/2. 2'log 3 = m + 1
1/2 . 2'log 3 = m + 1/2
2'log 3 = 2(m+1/2) = 2m+1
9'log 8 = (3^2)'log (2^3)  = 3/2 . 3'log 2
= (3/2) ( 1/(2m+1)
= 3/ (4m+2)