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= 4 . 460 . (70-20)
= 1840 . 50
= 92000 Joule
= 92 KJ
kenaikan suhu △t = 70° - 20° = 50°
kalor jenis besi (c) = 460 j/kg°C
kalor yg d perlukan(Q) = ?
Q = m.c.△t
= 4.50.460
= 92000 joule.
jadi kalor yg diperlukan/energi yg diperlukan adalah 92000 joule
semoga dapat membantu.