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Lim (x + x² × √x + x³ - x!!!!! + (2)x² ÷ x(2) + x²)
x → 20
20 + 20² × √20 + 20³ - 20!!!!! + (2)20² ÷ 20(2) + 20²
= 20 + 400 × √20 + 8.000 - (20.15.10.5) + (2)400 ÷ 40 + 400
= 20 + 400√20 + 8.000 - 15.000 + 800 ÷ 40 + 400
= 8.020 + 400√20 - 15.000 + 20 + 400
= -6.980 + 400√20 + 20 + 400
= -6.960 + 400√20 + 400
= -6.560 + 400√20
f(x) = 6x + 7x³ - 9x⁶ + 5x² + 1x
f'(x) = (1)6 + (3)7x³ - ¹ - (6)9x^6 - 5 + (2)5x² - ¹ + (1)1
f'(x) = 6 + 21x² - 54x^5 + 10x + 1
f'(x) = -54x^5 + 21x² + 10x + 7
f"(x) = (5)-54x^5 - 1 + (2)21x² - ¹ + (1)10 + 0
f"(x) = -270x⁴ + 42x + 10
f"(6) = -270(6⁴) + 42(6) + 10
f"(6) = -270(1.296) + 42(6) + 10
f"(6) = -349.920 + 252 + 10
f"(6) = -349.920 +262
f"(6) = -349.658
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SOAL 1
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Lim (x + x² × √x + x³ - x!!!!! + (2)x² ÷ x(2) + x²)
x → 20
20 + 20² × √20 + 20³ - 20!!!!! + (2)20² ÷ 20(2) + 20²
= 20 + 400 × √20 + 8.000 - (20.15.10.5) + (2)400 ÷ 40 + 400
= 20 + 400√20 + 8.000 - 15.000 + 800 ÷ 40 + 400
= 8.020 + 400√20 - 15.000 + 20 + 400
= -6.980 + 400√20 + 20 + 400
= -6.960 + 400√20 + 400
= -6.560 + 400√20
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SOAL 2
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f(x) = 6x + 7x³ - 9x⁶ + 5x² + 1x
f'(x) = (1)6 + (3)7x³ - ¹ - (6)9x^6 - 5 + (2)5x² - ¹ + (1)1
f'(x) = 6 + 21x² - 54x^5 + 10x + 1
f'(x) = -54x^5 + 21x² + 10x + 7
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f"(x) = (5)-54x^5 - 1 + (2)21x² - ¹ + (1)10 + 0
f"(x) = -270x⁴ + 42x + 10
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f"(6) = -270(6⁴) + 42(6) + 10
f"(6) = -270(1.296) + 42(6) + 10
f"(6) = -349.920 + 252 + 10
f"(6) = -349.920 +262
f"(6) = -349.658
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