A+B=C D-C=A D-B=A2 B=3/4 dari D D=akar dari 16 Berapakah nilai C?
timpukbenjol
D = akar 16 --> D = 4 B = 3/4 D --> (3/4) x 4 --> B = 3 D - B = A2 --> 4 - 3 = A2 --> A = 1/2 D - C = A --> C = D - A = 4 - 1/2 --> (8/2) - (1/2) = 7/2
D = 4, C = 7/2, B = 3, A = 1/2
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krismonhidayatD = D = 4 B = D B = x 4 B = 3 D - B = A2 4 - 3 = A2 A = D - C = A C = D - A C = 4 - = - =
B = 3/4 D --> (3/4) x 4 --> B = 3
D - B = A2 --> 4 - 3 = A2 --> A = 1/2
D - C = A --> C = D - A = 4 - 1/2 --> (8/2) - (1/2) = 7/2
D = 4, C = 7/2, B = 3, A = 1/2
D = 4
B = D
B = x 4
B = 3
D - B = A2
4 - 3 = A2
A =
D - C = A
C = D - A
C = 4 - = - =
jadi:
D = 4,
C = ,
B = 3 ,
A =