persamaan kuadrat yang akar-akarnya -6 dan 3/4 adalah.... Question from @ajsksksjhsbsjs

$\mathbb{ \color{aqua}{ \underbrace{JAWABAN}}}$

$\boxed{ \bf{ \: {4x}^{2} + 21x - 18 = 0 \: }}$

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$\mathbb{ \color{orange}{ \underbrace{PENYELESAIAN}}}$

$\boxed{ \: \begin{aligned} \tt{(x - x_{1})(x - x_{2})} &= \tt{0} \\ \tt{ \left(x - ( - 6) \right) \left(x - \frac{3}{4} \right)} &= \tt{0} \\ \tt{ \left(x + 6 \right) \left(x - \frac{3}{4} \right)} &= \tt{0} \\ \tt{ {x}^{2} - \frac{3}{4} x + 6x - \frac{18}{4} } &= \tt{0} \\ \tt{4 \left( {x}^{2} - \frac{3}{4} x + 6x - \frac{18}{4} \right)} &= \tt{4(0)} \\ \tt{ {4x}^{2} - 3x + 24x - 18} &= \tt{0} \\ \bf{ \pink{ {4x}^{2} + 21x - 18}}& \pink{=} \bf{ \pink{0}} \end{aligned} \: }$

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$\mathbb{ \color{red}{ \underbrace{KESIMPULAN}}}$

Jadi, persamaan kuadrat yang akar-akarnya -6 dan ¾ adalah 4x² + 21x - 18 = 0

$\colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{}$

2 votes Thanks 3

KellDSini

Penjelasan dengan langkah-langkah:

(x - x1)(x - x2) = 0

(x - (-6))(x - ¾) = 0

(x + 6)(x - ¾) = 0

x(x - ¾) + 6(x - ¾) = 0

x² - ¾x + 6x - 18/4 = 0

x² - ¾x + 24/4x - 9/2 = 0

x² + 21/4x - 9/2 = 0

0 votes Thanks 0

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