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Verified answer
Persamaan KuadratKelas X
Persamaan kuadrat yang akar-akarnya α = - ½ , β = ¼ adalah
Persamaannya :
x² - (α + β)x + αβ = 0
x² - (-½ + ¼)x + (-½)(¼) = 0
x² + ¼ x - ⅛ = 0
Jawaban : B
Verified answer
Mapel : MatematikaBab : Persamaan Kuadrat
Diketahui :
- Akar 1 = - 1/2
- Akar 2 = 1/4
Ditanya :
- Persamaan Kuadrat Berakar - 1/2 dan 1/4 = .....?
Penyelesaian :
- Persamaan Kuadrat Berakar - 1/2 dan 1/4 :
a. Akar 1 :
x = - 1/2
x + 1/2 = 0
b. Akar 2 :
x = 1/4
x - 1/4 = 0
c. Persamaan Kuadrat :
(x + 1/2)(x - 1/4)
= (x × x) - (x × 1/4) + (1/2 × x) - (1/2 × 1/4)
= x² - 1/4x + 1/2x - 1/8
= x² + (- 1 + 2)/4x - 1/8
= x² + 1/4x - 1/8
Jawaban : B. x² + 1/4x - 1/8
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