[tex]( \frac{2}{14} \times 0.2) - \frac{5}{4} = ( \frac{2}{14} \times \frac{2}{10} ) - \frac{5}{4} \\ \\ = ( \frac{1}{7} \times \frac{1}{5} ) - \frac{5}{4} = \frac{1}{35} - \frac{5}{4} \\ \\ = \frac{4 - 175}{140} = - \frac{171}{140} = - 1 \frac{31}{140} [/tex]
[tex] \frac{4}{8} + ( \frac{25}{100} \times \frac{1}{4} ) = \frac{1}{2} + ( \frac{1}{4} \times \frac{1}{4} ) \\ \\ = \frac{1}{2} + \frac{1}{16} = \frac{8 + 1}{16} = \frac{9}{16} [/tex]
[tex] \frac{2}{5} - (\frac{1}{2} \div \frac{1}{4} ) = \frac{2}{5} - ( \frac{1}{ \cancel2} \times \frac{ \cancel4^{2} }{1} ) \\ \\ = \frac{2}{5} - \frac{2}{1} = \frac{2 - 10}{5} = - \frac{8}{5} = - 1 \frac{3}{5} [/tex]
[tex]( - \frac{6}{8} \times ( - \frac{2}{10} )) + \frac{3}{4} = ( - \frac{3}{4} \times ( - \frac{1}{5} )) + \frac{3}{4} \\ \\ = \frac{3}{20} + \frac{3}{4} = \frac{3 + 15}{20} = \frac{18}{20} = \frac{9}{10} [/tex]
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No. 1
[tex]( \frac{2}{14} \times 0.2) - \frac{5}{4} = ( \frac{2}{14} \times \frac{2}{10} ) - \frac{5}{4} \\ \\ = ( \frac{1}{7} \times \frac{1}{5} ) - \frac{5}{4} = \frac{1}{35} - \frac{5}{4} \\ \\ = \frac{4 - 175}{140} = - \frac{171}{140} = - 1 \frac{31}{140} [/tex]
No. 2
[tex] \frac{4}{8} + ( \frac{25}{100} \times \frac{1}{4} ) = \frac{1}{2} + ( \frac{1}{4} \times \frac{1}{4} ) \\ \\ = \frac{1}{2} + \frac{1}{16} = \frac{8 + 1}{16} = \frac{9}{16} [/tex]
No. 3
[tex] \frac{2}{5} - (\frac{1}{2} \div \frac{1}{4} ) = \frac{2}{5} - ( \frac{1}{ \cancel2} \times \frac{ \cancel4^{2} }{1} ) \\ \\ = \frac{2}{5} - \frac{2}{1} = \frac{2 - 10}{5} = - \frac{8}{5} = - 1 \frac{3}{5} [/tex]
No. 4
[tex]( - \frac{6}{8} \times ( - \frac{2}{10} )) + \frac{3}{4} = ( - \frac{3}{4} \times ( - \frac{1}{5} )) + \frac{3}{4} \\ \\ = \frac{3}{20} + \frac{3}{4} = \frac{3 + 15}{20} = \frac{18}{20} = \frac{9}{10} [/tex]