[tex]\dfrac{(\frac{4}{10}-1)\cdot(3\frac{1}{3}-2,5)}{1\frac{3}{4}}=\dfrac{(\frac{2}{5}-1)\cdot(\frac{10}{3}-\frac{25}{10})}{\frac{7}{4}}=\dfrac{(\frac{2}{5}-\frac{5}{5}) \cdot(\frac{10}{3}-\frac{5}{2})}{\frac{7}{4}}=\\\\\\=\dfrac{-\frac{3}{5}\cdot(\frac{20}{6}-\frac{15}{6})}{\frac{7}{4}}=\dfrac{-\frac{\not3^1}{\not5_{1}}\cdot\frac{\not5^1}{\not6_{2}}}{\frac{7}{4}}=\dfrac{-\frac{1}{2}}{\frac{7}{4}}=-\frac{1}{2}:\frac{7}{4}=-\frac{1}{\not2_{1}}\cdot\frac{\not4^2}{7}=-\frac{2}{7}[/tex]
Odpowiedź:
(4/10-1)*(3 1/3-2,5):1 3/4=
(4/10-10/10)*(10/3-25/10):7/4=
-6/10*(10/3-5/2)7/4=
-3/5*(20/6-15/6); 7/4=
-3/5*5/6:7/4=
-15/30:7/4=
-3/6*4/7=
-12/42=
-3/4
Szczegółowe wyjaśnienie:
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[tex]\dfrac{(\frac{4}{10}-1)\cdot(3\frac{1}{3}-2,5)}{1\frac{3}{4}}=\dfrac{(\frac{2}{5}-1)\cdot(\frac{10}{3}-\frac{25}{10})}{\frac{7}{4}}=\dfrac{(\frac{2}{5}-\frac{5}{5}) \cdot(\frac{10}{3}-\frac{5}{2})}{\frac{7}{4}}=\\\\\\=\dfrac{-\frac{3}{5}\cdot(\frac{20}{6}-\frac{15}{6})}{\frac{7}{4}}=\dfrac{-\frac{\not3^1}{\not5_{1}}\cdot\frac{\not5^1}{\not6_{2}}}{\frac{7}{4}}=\dfrac{-\frac{1}{2}}{\frac{7}{4}}=-\frac{1}{2}:\frac{7}{4}=-\frac{1}{\not2_{1}}\cdot\frac{\not4^2}{7}=-\frac{2}{7}[/tex]
Odpowiedź:
(4/10-1)*(3 1/3-2,5):1 3/4=
(4/10-10/10)*(10/3-25/10):7/4=
-6/10*(10/3-5/2)7/4=
-3/5*(20/6-15/6); 7/4=
-3/5*5/6:7/4=
-15/30:7/4=
-3/6*4/7=
-12/42=
-3/4
Szczegółowe wyjaśnienie: