Question

Integral dari x / (4-3x^2)^2 dx

Answer 1

Verified answer

Misal :
u = 4 - 3x²
du/dx = -6x
x dx = -1/6 du

∫x/(4 - 3x²)² dx
= ∫u^-2 . -1/6 du
= -1/6 . 1/(-1) . x^-1 + C
= 1/(6(4 - 3x²)) + C
= 1/(24 - 18x²) + C