Question

Jawaban dari
6/3+2√2-3/4-3√3=

Answer 1

Mungkin yg dimaksud soalnya seperti ini

= (6 / (3+2√2)) - (3 / (4-3√3))
= (24-18√3 - 9+6√2) / 12-6√6
= (15 - 18√3 + 6√2) / 12-6√6
= (5 - 6√3 + 2√2) / 4 - 2√6
= (5-6√3+2√2)(4+2√6) / 16-24
= (20 + 10√6 - 24√3 - 12√18 + 8√2 + 4√12) / (-8)
= (-10 - 5√6 +12√3 - 6√18 + 4√2 + 2√12) / 4
=  (-10 - 5√6 +12√3 - 6√9*2 + 4√2 + 2√4*3) / 4 
=  (-10 - 5√6 +12√3 - 18√2 + 4√2 + 4√3) / 4
=  (-10 - 5√6 + 16√3 - 12√2) / 4

Answer 2

Rasionalkan satu-satu pecahannya :
6/(3+2√2) = 6/(3+2√2) x (3 - 2√2)/(3 - 2√2) = 6(3 - 2√2)/(9-8) = 18 - 12√2

3/(4 - 3√3) = 3/(4 - 3√3) x  (4 + 3√3)/(4 + 3√3)
 = 3(4 + 3√3)/(16 - 27) =  -3/11 (4 + 3√3)

kurangi, get
(18 - 12√2) - (-3/11 (4 + 3√3))
= 18 - 12√2 +  12/11 + 9/11 √3