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5y=15-3x
y=(15-3x)/5
Sustituyendo:
2x-3[(15-3x)/5]=-9
10x-45+9x=-45
19x=0
x=0
Reemplazando en y:
y=[15-3x]/5
y=[15-3(0)]/5
y=[15-0]/5
y=15/5
y=3
Metodo de sustitución.
3x + 5y = 15 (1)
2x - 3y = - 9 (2)
Despejas x de (2)
2x - 3y = - 9
2x = 3y + 9
x = (3y - 9)/2 Sustituyes este valor en (1)
3x + 5y = 15
3(3y - 9)/2 + 5y = 15
(9y - 27)/2 + 5y = 15
(9y - 27)/2 + 10y/2 = 30/2 Simplificas el 2
9y - 27 + 10y = 30
19y - 27 = 30
19y = 30 + 27
19y = 57
y = 57/9
y = 3 Rempazas este valor en (1)
3x + 5y = 15
3x + 5(3) = 15
3x + 15 = 15
3x = 15 - 15
3x = 0
x = 0/3
x = 0
Solución.
(0 , 3)