Question

F(x) = 2/3(x–5). jika f￣¹(p) = 11 maka nilai p =

mohon bantuannya ya ☺
ありがとう

Answer 1

F(x) = 2/3 (x - 5)
y = 2/3 (x - 5)
3/2 y = x - 5
3/2 y + 5 = x
f-1 (y) = 3/2 y + 5
f-1 (x) = 3/2 x + 5
jika f-1 (p) = 11 maka berlaku:
11 = 3/2 p + 5
11 - 5 = 3/2 p
6 = 3/2 p
6 * 2 / 3 = p
4 = p
jadi nilai p adalah 4.

Answer 2

F^-1(p) = 11 => f(11) = p = 2/3 (11 - 5) = 2/3 (6) = 12/3 = 4