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1) 3x + 2y = 12
2) x + 2y = 16
Despejo x en las dos ecuaciones
3x + 2y = 12 x + 2y = 16
3x = 12 - 2y x = 16 - 2y
x = (12 - 2y)/3 x = (16 - 2y)/1
Igualamos las dos ecuaciones y multiplicamos en cruz.
(12 - 2y)/3 = (16 - 2y)/1
1 (12 - 2y) = 3 (12 - 2y)
12 - 2y = 36 - 6y
- 2y + 6y = 36 - 12
4y = 24
y = 24/4
y = 6
El valor de y lo reemplazo en uno de los despeje de x
x = (16 - 2y)/1
x = (16 - 2 (6))/1
x = (16 - 12)/1
x = 4/1
x = 4
Respuesta.
x = 4
y = 6