Question

3x+2y-12=0 dan x+2y=4. Tolong dihitung menggunakan Metode Subtitusi..

Answer 1

3x + 2y = 0 + 12

x + 2y = 4

3x + 2y = 12 ... ( 1 )

x + 2y = 4 ... ( 2 )

x = - 2y + 4 ... ( 3 )

Substitusikan ( 3 ) ke ( 1 )

3( - 2y + 4 ) + 2y = 12

- 6y + 12 + 2y = 12

- 4y = 12 - 12

- 4y = 0

y = 0

Substitusikan 0 ke ( 3 )

x = - 2( 0 ) + 4

x = 0 + 4

x = 4

Maka, ( x = 4 dan y = 0 )