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Verified answer
Grafikf(x) = ⅓x³ - x² - 15x + 7
nilai stasioner fungsi Apabil f' (x) = 0
maka fungsi turunannya
f '(x) = x² - 2x - 15
f'(x) = (x - 5) (x + 3)
x = 5 atau x = -3
masukan ke fungsinya
f(5) = ⅓(5)³ - (5)² - 15(5) + 7 = -51 (⅓)
f(-3) = ⅓(-3)³ - (-3)² - 15(-3) + 7 = 34
maka titik stasionernya (5, -51 ⅓) dan (-3, 34)