Question

3x² + 8x + 4 = 0 selesaikan dengan menggunakan rumus kuadratis.​

Answer 1

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rumus kuadratis

3x² + 8x + 4 = 0 selesaikan dengan menggunakan rumus kuadratis.​
a= 3
b = 8
c= 4

[tex]\sf x_{12} = \dfrac{-b\pm \sqrt{b^2 -4ac}}{2a}[/tex]

[tex]\sf x_{12} = \dfrac{-8\pm \sqrt{8^2 -4(3)(4)}}{2(3)}[/tex]

[tex]\sf x_{12} = \dfrac{-8\pm \sqrt{64- 48}}{6}[/tex]

[tex]\sf x_{12} = \dfrac{-8\pm \sqrt{16}}{6}[/tex]

[tex]\sf x_{12} = \dfrac{-8\pm 4}{6}[/tex]

[tex]\sf x_{1} = \dfrac{-8+4}{6} = -\dfrac{4}{6} = - \dfrac{2}{3}[/tex]

[tex]\sf x_{2} = \dfrac{-8-4}{6} = -\dfrac{12}{6} = -2[/tex]