Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]f(x)=\frac{2}{3} (x-6)^{2} -20 \\[/tex]
[tex]f(x)=\frac{2}{3} (x^{2} -12x+36)-20\\[/tex]
[tex]f(x)=\frac{2}{3} x^{2} -8x+4\\[/tex]
Δ = [tex]b^{2} -4ac=8^{2} -4*\frac{2}{3} *4=64-\frac{32}{3} =\frac{160}{3} =53\frac{1}{3}[/tex]
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Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]f(x)=\frac{2}{3} (x-6)^{2} -20 \\[/tex]
[tex]f(x)=\frac{2}{3} (x^{2} -12x+36)-20\\[/tex]
[tex]f(x)=\frac{2}{3} x^{2} -8x+4\\[/tex]
Δ = [tex]b^{2} -4ac=8^{2} -4*\frac{2}{3} *4=64-\frac{32}{3} =\frac{160}{3} =53\frac{1}{3}[/tex]