Wykresy w załączniku!
a)
2/3x + 4 = 0
2/3x = -4
x = -4 * 3/2 = -6
f(x) < 0 ⇔ x ∈ (-∞ ; -6)
2/3x + 4 = 2
2/3x = -2
x = -2 * 3/2 = -3
f(x) > 2 ⇔ x ∈ (-3 ; +∞)
b)
-3x + 5 = 0
-3x = -5
x = 5/3
f(x) < 0 ⇔ x ∈ (5/3 ; +∞)
-3x + 5 = 2
-3x = -3
x = 1
f(x) > 2 ⇔ x ∈ (-∞ ; 1)
c)
-2,5x - 3 = 0
-2,5x = 3
x = -6/5
f(x) < 0 ⇔ x ∈ (-6/5 ; +∞)
-2,5x - 3 = 2
-2,5x = 5
x = -2
f(x) > 2 ⇔ x ∈ (-∞ ; -2)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Wykresy w załączniku!
a)
2/3x + 4 = 0
2/3x = -4
x = -4 * 3/2 = -6
f(x) < 0 ⇔ x ∈ (-∞ ; -6)
2/3x + 4 = 2
2/3x = -2
x = -2 * 3/2 = -3
f(x) > 2 ⇔ x ∈ (-3 ; +∞)
b)
-3x + 5 = 0
-3x = -5
x = 5/3
f(x) < 0 ⇔ x ∈ (5/3 ; +∞)
-3x + 5 = 2
-3x = -3
x = 1
f(x) > 2 ⇔ x ∈ (-∞ ; 1)
c)
-2,5x - 3 = 0
-2,5x = 3
x = -6/5
f(x) < 0 ⇔ x ∈ (-6/5 ; +∞)
-2,5x - 3 = 2
-2,5x = 5
x = -2
f(x) > 2 ⇔ x ∈ (-∞ ; -2)