Question

[3(x-1)²]² = pake caranya ya

Answer 1

[3(x-1)(x-1)]² = [3(x²-2x+1)]² = (3x²-6x+3)²= 9 x^4 - 36 x²+9

Answer 2

(3(x-1)²)² =
 kerjakan dahulu yg dlm kurung (x-1)² = (x²-2x+1)² = x^4-4x²+1
dikalikan 3² = 9 x (x^4-4x²+1 = 9x^4-36x²+9
jd, 9x^4-36x²+9