Respuesta:
( \frac{1}{2}m+ \frac{2}{3}n) ( \frac{1}{2}m+ \frac{2}{3}n) = \frac{1}{4}m^{2} + \frac{2}{6}mn+ \frac{2}{6}mn+ \frac{4}{9}n ^{2} =(
2
1
m+
3
n)(
n)=
4
m
+
6
mn+
9
n
= \frac{1}{4}m ^{2}+ \frac{4}{6}mn+ \frac{4}{9}n
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Respuesta:
( \frac{1}{2}m+ \frac{2}{3}n) ( \frac{1}{2}m+ \frac{2}{3}n) = \frac{1}{4}m^{2} + \frac{2}{6}mn+ \frac{2}{6}mn+ \frac{4}{9}n ^{2} =(
2
1
m+
3
2
n)(
2
1
m+
3
2
n)=
4
1
m
2
+
6
2
mn+
6
2
mn+
9
4
n
2
= \frac{1}{4}m ^{2}+ \frac{4}{6}mn+ \frac{4}{9}n
4
1
m
2
+
6
4
mn+
9
4
n