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x + y = 6
y + z = 7
z + x = 9
----------------------
2x+2y+2z = 22 dividimos para 2
x+y+z = 11
reemplazo y+z = 7 en x+y+z = 11
x+ 7 = 11
x= 4
reemplazo x= 4 en x+y= 6
4+y= 6
y= 2
reemplazo y = 2 en y+z =7 x=4
2 +z = 7 y= 2
z= 5 z= 5
al tener los valores de x,y,z reemplazamos en (x+y+z)/3=
(4+2+5) 11
------------- = ---- = 3,66 RTA la D 11/3
3 3