April 2019 1 11 Report
A.-(-2.34)°=
B.-(5/7)°=
C.-(-π)°=
D.- 5³×5 elevada ala 4 =
E.-∛7² ÷∛7 elevada a la 4=
F.-(-3/5)³× (-3/5)²=
G.-(0,123)³×(7)³=
H.-(2/5) elevada a la 4 × (2/5) elevada a la 4 =
I.-(-2)²×(-2)²=
J.-(3/5) elevada a la 4 ÷ (3/5)³=
K.-√2 elevada a la 5 ÷ √2 ³=
L.-(-5) elevada ala 5 ÷(-5) elevada a la 6=
M.-4 √6 elevado al 1 =
N.-(5/3)²=
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