Question

Diketahui fungai f(×)=2/3×+b.jika f(b)=b+2, nilai f(-b)=....
(kalau bisa pakai caranya)

Answer 1

F(b)=2/3(b)+b
=2b/3+3b/3
=5b/3
5b/3=b+2
5b=3(b+2)
5b=3b+6
5b-3b=6
2b=6
b=3
f(-b)=f(-3)=-3+2=-1